I am curious as to what you are using it for now.
I have gone through several calculations and have yet to find the correct one that gives me the same answer as yours.
480 volts from 32 - 53 watt PV modules rated at 47 Vmax. and 1.2 Imax. each.
If I divide 53 by 47 I get 1.1
If I divide 53 by 1.2 I get 44.1
Obviously 4 times 8 is 32
But how to derive 480 from 32 times 47?
4 strings of 8
8 x 47 = 376 (If 47 is the max volts then the working volts would lower)
Maybe, if you have 2 of those modules "sitting on the bench" then in a since you have 3 sets of 10 but thats still only 470 Vmax.
Its curious that you would mention these modules and there ratings if you did not feel that it is relevant to your ultimate question of, where to find an inverter to run on 1.2 amps at 480 vdc. Even more curious is that you did not mention the average expected number of hours of power production per day, averaged out over the year. I am going to guess 5. So,
32 x 53 x 5 / 1000 x .10 x 365 = $309.52
if your lucky enough to get $0.10 per kilowatthour. Heres to sunny days.
Anyway, if your on the internet reading this then you have access to a search engine of some kind. Just type in - 480 vdc inverter - and this will get you several hits for inverters that have an input voltage that ranges from as low as 250 vdc to 480 vdc. Here is one of many.
http://www.zapsucker.com/intrface.htmPrepare yourself, when you go on the grid with this kind of power it could make feel like your a bug under a microscope?
