Required Solar Power Agricultural Water Pump

Posted by Thomas Allen Schmidt on January 23, 2009, 07:19:16 PM

Re: Required Solar Power Agricultural Water Pump (Reply #5)
One way you can estimate the size PV array needed to power the pumping station is to look at the power bill. It should state how many kWh's (kilo Watt hours) are used in a month.

For example:
Lets say the pumping station consumes 200 kWh's per month during pumping season. We all know that to be the same as 200,000 watt hours.

Now we need to know the number of hours of equivalent full rated power output from a PV module.
What that means is, a PV modules power output starts out low in the morning, gradually rises to near peak output at noon and then, power output starts going back down into the evening. So we add that all up and divide it by a PV modules output.

I am going to use 5 hours of equivalent full rated power output in my example.
200,000 watt hours divided by 30 days = 6,667 watt hours per 24 hours day/night. If the pumps run day and night on utility power then divide that in half for 3,334 watt hours per day if you want it to run from just PV power with no batteries for night time use. Or if you want a utility intertied system and want to offset nightime power consumption use the the full 6,667 watt hours.

3,334 watt hours divided by 5 = 667 watt PV array.

Remember this is just an example. Don't use these figures to size your PV array.

A review of the math:
200 x 1,000 = 200,000
200,000 / 30 = 6,667
6,667 / 2 = 3,334
3,334 / 5 = 667

The biggest things you need to know are:
kilowatthours consumed by the pumping station for one, twelve hour day and, the number of hours of equivalent full rated power output of a PV module per day in your area.
 

Posted by Thomas Allen Schmidt on January 24, 2009, 04:01:36 PM

Re: Required Solar Power Agricultural Water Pump (Reply #6)
I just want to add that here in America a typical single family dwelling will use about 1,000 to 1,500 kWh's a month and, there is an over all average of about 3 to 4 hours of equivalent full rated power output from a PV module per day but, this is averaged out over the entire country and the year. Winter months will be lean while Summer months might show a surplus.
Also, PV sells for about U.S.$5.00 per watt, not installed.

1,500 x 1,000 = 1,500,000 watt hours per month.
1,500,000 / 30 = 50,000 watt hours per day.
50,000 / 3 = 16,667 watt PV array.
16,667 x $5.00 = $83,335.00 dollars.

If that same dwelling was paying the utilities $0.10 per kWh, that would be, $150.00 per month. If it payed that amount for 50 years that would be $90,000 dollars.

The photovoltaics industry is going to get its share!

 

Posted by Maarten De Coster on February 03, 2009, 01:25:05 PM

Re: Required Solar Power Agricultural Water Pump (Reply #7)
Hello Aziz,

Our company provides solar power water pumps and other water solutions for customers worldwide.

Would you please be so kind to tell us more about your project and what you require?

Thanks in advance!

Maarten.
 

Posted by Aziz Safi on February 09, 2009, 04:44:17 PM

Re: Required Solar Power Agricultural Water Pump (Reply #8)
Hello Aziz,

Our company provides solar power water pumps and other water solutions for customers worldwide.

Would you please be so kind to tell us more about your project and what you require?

Thanks in advance!

Maarten.
 

Posted by Maarten De Coster on February 09, 2009, 04:49:41 PM

Re: Required Solar Power Agricultural Water Pump (Reply #9)
Hello Aziz,

We are looking forward to your answer.

Best regards,

Maarten.
 
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